Let's call 0.999999999999999999999999999999 recurring "x" then, 10x = 9.9999999999999999999999999999 recurring Then: 10x - x Which is equal to: 9.999999999999999999999999999999 recurring - 0.999999999999999999999999999999 recurring ==> 9x = 9 so 0.9999999 recurring = x = 1. The End.

so. Now what?

We dance?

OMG, it's teh IR15H!!!!111 And he brought some maths along!! cute!

Wraith 5We dance?[/quote] Play that funky music, [person of equally important skin color] [person of equally important gender]. [quote=Mr yoki]OMG, it's teh IR15H!!!!111 And he brought some maths along!! cute!

Hello Mr yoki, how are you treating the music forum these days? Because you enjoyed the maths so much; If we express 1/3 as a decimial = 0.333333 recurring. If we times 0.33333 recurring by three we get 0.999999 recurring. If we do 3 x 1/3 (or 0.3333 recurring) we get 1. So; 0.99999 recurring = 1.

that's not 100%ly correct. 1/3 = 0.3 period and 0.3 period * 3 = 1.0 not 0.9 period. The number 0.9 period is non-existent ;)

Not quite, it would come infinitely close. Same logic as .00000(infinite 0's)0001 is not the same as 0, because you can divide by it.

The_Yokithat's not 100%ly correct. 1/3 = 0.3 period and 0.3 period * 3 = 1.0 not 0.9 period. The number 0.9 period is non-existent ;)[/quote] Meow? 3 x 0.3 = 0.9 3 x 0.33 = 0.99 3 x 0.333 = 0.999 3 x 0.3333 = 0.9999 etc. But anyway, 0.9r is 1 :nodding: [quote=Pb2Au]Not quite, it would come infinitely close. Same logic as .00000(infinite 0's)0001 is not the same as 0, because you can divide by it.

You can not have an infinte number of zeros and then have a 1 at the end, infinte means it has no end. If 0.9r is not 1 then name a number in between the two.

For every single digit you add, it'll always be that little bit away from 1
.9 is .1 away from 1
.99 is .01 away
.999 is .001 away
and so on
You will never, ever, be at exactly 1, because the number is *not *1, it is .9r

- 1
- 2