# 0.9999999999 reccurring = 1. 19 replies

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IR15H

An end has a start.

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7th September 2005

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#1 14 years ago

Let's call 0.999999999999999999999999999999 recurring "x" then, 10x = 9.9999999999999999999999999999 recurring Then: 10x - x Which is equal to: 9.999999999999999999999999999999 recurring - 0.999999999999999999999999999999 recurring ==> 9x = 9 so 0.9999999 recurring = x = 1. The End.

Guest

I didn't make it!

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#2 14 years ago

if you say so....

IR15H

An end has a start.

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7th September 2005

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#3 14 years ago

so. Now what?

Wraith 5

The Fun cannot be Halted!

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11th October 2005

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#4 14 years ago

We dance?

The_Yoki

"Germany's finest Hippie"

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21st August 2005

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#5 14 years ago

OMG, it's teh IR15H!!!!111 And he brought some maths along!! cute!

IR15H

An end has a start.

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7th September 2005

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#6 14 years ago
Wraith 5We dance?[/quote] Play that funky music, [person of equally important skin color] [person of equally important gender]. [quote=Mr yoki]OMG, it's teh IR15H!!!!111 And he brought some maths along!! cute!

Hello Mr yoki, how are you treating the music forum these days? Because you enjoyed the maths so much; If we express 1/3 as a decimial = 0.333333 recurring. If we times 0.33333 recurring by three we get 0.999999 recurring. If we do 3 x 1/3 (or 0.3333 recurring) we get 1. So; 0.99999 recurring = 1.

The_Yoki

"Germany's finest Hippie"

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21st August 2005

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#7 14 years ago

that's not 100%ly correct. 1/3 = 0.3 period and 0.3 period * 3 = 1.0 not 0.9 period. The number 0.9 period is non-existent ;)

Pb2Au

Droolworthy

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4th October 2004

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#8 14 years ago

Not quite, it would come infinitely close. Same logic as .00000(infinite 0's)0001 is not the same as 0, because you can divide by it.

IR15H

An end has a start.

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7th September 2005

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#9 14 years ago
The_Yokithat's not 100%ly correct. 1/3 = 0.3 period and 0.3 period * 3 = 1.0 not 0.9 period. The number 0.9 period is non-existent ;)[/quote] Meow? 3 x 0.3 = 0.9 3 x 0.33 = 0.99 3 x 0.333 = 0.999 3 x 0.3333 = 0.9999 etc. But anyway, 0.9r is 1 :nodding: [quote=Pb2Au]Not quite, it would come infinitely close. Same logic as .00000(infinite 0's)0001 is not the same as 0, because you can divide by it.

You can not have an infinte number of zeros and then have a 1 at the end, infinte means it has no end. If 0.9r is not 1 then name a number in between the two.

Pb2Au

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4th October 2004

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