REAL math question 11 replies

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#1 7 years ago

Be so kind as to expand this, separate the variables so you get the radial and angular equations, and then solve each for Helium, nay, URANIUM, using the variational method.

See you in 30 years.

ham.png




Red Menace

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#2 7 years ago

Done. Next?


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#3 7 years ago

^ genius




Schofield VIP Member

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#4 7 years ago

(h2 OVER 2u UPSIDE DOWN TRIANGLE2 - Ze2 OVER r - E) FUCKED UP LOOKING u (r, 0, FUCKED UP LOOKING o) = 0




Nittany Tiger Forum Mod

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#5 7 years ago

[COLOR="Magenta"]You know that the interactions between the electrons of uranium have not been modeled successfully in a mathematical sense. Why I have no doubt that this equation can be solved analytically, it cannot be done without taking a step back to model V properly (Ze^2/r is only an approximation of V).

Since you are using an approximation, why bother with an analytical solution?[/COLOR]




Embee

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#6 7 years ago

FACK YOU PEOPLE WHO UNDERSTAND THIS SHIT!




Schofield VIP Member

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#7 7 years ago

Lisa-Marie.jpg




Embee

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#8 7 years ago
Schofield;5573509Lisa-Marie.jpg

Fuck math, LET'S ROLL BISHES!




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#9 7 years ago

Exactly. Why do math when you can do that? Fuck the red hair though.:cort:




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#10 7 years ago

Killer Kyle;5573507[COLOR=Magenta]You know that the interactions between the electrons of uranium have not been modeled successfully in a mathematical sense. Why I have no doubt that this equation can be solved analytically, it cannot be done without taking a step back to model V properly (Ze^2/r is only an approximation of V).

Since you are using an approximation, why bother with an analytical solution?[/COLOR]

I only gave the equation to explain what was to be attempted because I don't want to explain variational method. It's impossible (literally) to find an analytical solution if you included electron interactions. As for the Ze^2/r, it was the only picture of the equation in any form that didn't glitch horribly when posting it.




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