# Super Math Genius 10 replies

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Macaquinhos

O rly?

50 XP

12th May 2006

235 Posts

#1 12 years ago

----1---- ----2---- ----3---- ----4---- ----5----

LOLOLOLLOLOLOLOLOLOL that's my kind of math!!!! Calc AP FTL :(

is actually wrong anyway, limit of (1/x-8) while x is going 8 = does not exist.....not infinity, lol

lilbond

GF is my bext friend *hugs GF*

50 XP

7th June 2005

2,557 Posts

#2 12 years ago

Link no worko. you go fixo.

Macaquinhos

O rly?

50 XP

12th May 2006

235 Posts

#3 12 years ago

you can now lawl.

unDutchable

50 XP

23rd February 2004

6,449 Posts

#4 12 years ago

heh lol I like the "5" one :vikki:

KingSpicer

I follow teh Moo!

50 XP

16th November 2005

1,591 Posts

#5 12 years ago

excellent

Guest

I didn't make it!

0 XP

#6 12 years ago

thats funny

116,900 XP

10th April 2006

11,075 Posts

#7 12 years ago

:rofl:

lilbond

GF is my bext friend *hugs GF*

50 XP

7th June 2005

2,557 Posts

#8 12 years ago

yes, most funny indeed.

Pb2Au

Droolworthy

50 XP

4th October 2004

8,461 Posts

#9 12 years ago

Funny stuff...

'Macaquinhos'is actually wrong anyway, limit of (1/x-8) while x is going 8 = does not exist.....not infinity, lol

Uh... yeah it does, and it is infinity. As x -> 8, the denominator becomes smaller and smaller. For x = 7.9, f(x) = 1/.1 = 10 For x = 7.99, f(x) = 1/.01 = 100 So, as x -> 8, you divide 1 by an increasingly smaller number, which is the same as multiplying it by a bigger number. Because you can get a number infinitesimally close to 8 without it actually being '8' (think 7.999999999999999999...) it results in a limit of infinity. It's about the limit as x -> 8, not about f(8).

-EDIT-

Wait, no no no... you're right

A limit doesn't exist when the behaviour as the function approaches c from left and right sides differ. The one sided limit x -> 8 + would be inifinity, but because lim x -> 8 - would be negative infinity, the limit doesn't exist. Stupid of me...

Macaquinhos

O rly?

50 XP

12th May 2006

235 Posts

#10 12 years ago

Pb2AuFunny stuff...

Uh... yeah it does, and it is infinity. As x -> 8, the denominator becomes smaller and smaller. For x = 7.9, f(x) = 1/.1 = 10 For x = 7.99, f(x) = 1/.01 = 100 So, as x -> 8, you divide 1 by an increasingly smaller number, which is the same as multiplying it by a bigger number. Because you can get a number infinitesimally close to 8 without it actually being '8' (think 7.999999999999999999...) it results in a limit of infinity. It's about the limit as x -> 8, not about f(8).

-EDIT-

Wait, no no no... you're right

A limit doesn't exist when the behaviour as the function approaches c from left and right sides differ. The one sided limit x -> 8 + would be inifinity, but because lim x -> 8 - would be negative infinity, the limit doesn't exist. Stupid of me...

:0wned:

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